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IPv6 Questions 3

July 20th, 2017 in ROUTE 300-101 Go to comments

Question 1

Explanation

We need to summarize three IPv6 prefixes with /64 subnet mask so the summarized route should have a smaller subnet mask. As we can see all four answers have the same summarized route of 2001:DB8:: so /48 is the best choice.

Note: IPv6 consists of 8 fields with each 16 bits (8×16 = 128).

Question 2

Question 3

Question 4

Explanation

DHCPv6 can be implemented in two ways : Rapid-Commit and Normal Commit mode. In Rapid-Commit mode , the DHCP client obtain configuration parameters from the server through a rapid two message exchange (solicit and reply).

The “solicit” message is sent out by the DHCP Client to verify that there is a DHCP Server available to handle its requests.

The “reply” message is sent out by the DHCP Server to the DHCP Client, and it contains the “configurable information” that the DHCP Client requested.

Just for your information, in Normal-Commit mode, the DHCP client uses four message exchanges (solicit, advertise, request and reply). By default normal-commit is used.

Question 5

Explanation

The IPv6-to-IPv6 Network Prefix Translation (NPTv6) provides a mechanism to translate an inside IPv6 source address prefix to outside IPv6 source address prefix in IPv6 packet header and vice-versa. In other words, NPTv6 is simply rewriting IPv6 prefixes. NPTv6 does not allow to overload. It does not support mismatching prefix allocations sizes (so the network/host portion remains intact. For example you cannot cover /64 to /48).

Question 6

Question 7

Question 8

Question 9

Explanation

The automatic tunneling mechanism uses a special type of IPv6 address, termed an “IPv4-compatible” address. An IPv4-compatible address is identified by an all-zeros 96-bit prefix, and holds an IPv4 address in the low-order 32-bits. IPv4-compatible addresses are structured as follows:

ipv6toIPv4structure

Therefore, an IPv4 address of 10.67.0.2 will be written as ::10.67.0.2 or 0:0:0:0:0:0:10.67.0.2 or ::0A43:0002 (with 10[decimal] = 0A[hexa] ; 67[decimal] = 43[hexa] ; 0[hexa] = 0[decimal] ; 2[hexa] = 2[decimal])

Question 10

Comments
  1. Maineah
    August 5th, 2017

    Shouldn’t question 5 be A and F according to your explanation?

    > It does not support mismatching prefix allocations sizes

  2. Maineah
    August 5th, 2017

    Sorry I meant C and F

  3. Paco
    November 3rd, 2017

    Q1 I dont understand why the right answer isn’t C, I mean the more sumarized the better right? so /32 would be better or also valid. Please help me see if I am missing something

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